This is a simple solution that removes the need for any complex regex expression. My solution is to write a function that replaces any punctuation in the test string with spaces, and add a space to the beginning and end or the test string and test word, then return the number of occurrences. Otherwise, your function will have a hidden bug. The purpose of this example is to show that when you’re using conditional statements to provide multiple return statements, you need to make sure that every possible option gets its own return statement. This fails if the word is at the beginning or end of a sentence or is next to any punctuation. Python language offers some special types of operators like the identity operator and the membership operator. Now, myabs() checks every possible condition, number > 0, number < 0, and number 0. The reader object is then iterated using a for loop to print the contents of each row. Then, the csv.reader () is used to read the file, which returns an iterable reader object. To learn more about opening files in Python, visit: Python File Input/Output. One of the solutions is to put a space at the beginning and end of the test word. Here, we have opened the innovators.csv file in reading mode using open () function. >python -m timeit -s "def contains_word(s, w): return s.startswith(w + ' ') or s.endswith(' ' + w) or s.find(' ' + w + ' ') != -1" "contains_word('the quick brown fox', 'brown')"ġ000000 loops, best of 3: 1.13 usec per loopĮdit: A slight variant on this idea for Python 3.6+, equally fast: def contains_word(s, w): >python -m timeit -s "import re" -s "def contains_word(s, w): return re.compile(r'\b()\b'.format(w), flags=re.IGNORECASE).search(s)" "contains_word('the quick brown fox', 'brown')"ġ00000 loops, best of 3: 2.38 usec per loop Compared to Hugh Bothwell's and daSong's approaches: >python -m timeit -s "def contains_word(s, w): return (' ' + w + ' ') in (' ' + s + ' ')" "contains_word('the quick brown fox', 'brown')"ġ000000 loops, best of 3: 0.351 usec per loop Return (' ' + w + ' ') in (' ' + s + ' ')Ĭontains_word('the quick brown fox', 'brown') # TrueĬontains_word('the quick brown fox', 'row') # False is true -> delete c:log.txt and create a new c:log.txt My only problem is that I dont know how could create condition like: 1:00 AM. The log get generated by 'logging' module inside each python script from Scheduled Job and all results get logged to e.g. check if current time is between 23:59 PM and 1:00 AM 2. I have a python script monitor.py that analyzes text log. If you want to find out whether a whole word is in a space-separated list of words, simply use: def contains_word(s, w): I noticed that Scheduled Job on windows starts not exactly time it was scheduled but a few seconds before hence my prototype would be: 1.
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